Optimal. Leaf size=280 \[ -\frac{\sqrt{c} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt{d} \sqrt{c \sin (a+b x)}}{\sqrt{c} \sqrt{d \cos (a+b x)}}\right )}{\sqrt{2} b \sqrt{d}}+\frac{\sqrt{c} \tan ^{-1}\left (\frac{\sqrt{2} \sqrt{d} \sqrt{c \sin (a+b x)}}{\sqrt{c} \sqrt{d \cos (a+b x)}}+1\right )}{\sqrt{2} b \sqrt{d}}+\frac{\sqrt{c} \log \left (-\frac{\sqrt{2} \sqrt{d} \sqrt{c \sin (a+b x)}}{\sqrt{d \cos (a+b x)}}+\sqrt{c} \tan (a+b x)+\sqrt{c}\right )}{2 \sqrt{2} b \sqrt{d}}-\frac{\sqrt{c} \log \left (\frac{\sqrt{2} \sqrt{d} \sqrt{c \sin (a+b x)}}{\sqrt{d \cos (a+b x)}}+\sqrt{c} \tan (a+b x)+\sqrt{c}\right )}{2 \sqrt{2} b \sqrt{d}} \]
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Rubi [A] time = 0.188675, antiderivative size = 280, normalized size of antiderivative = 1., number of steps used = 10, number of rules used = 7, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.28, Rules used = {2574, 297, 1162, 617, 204, 1165, 628} \[ -\frac{\sqrt{c} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt{d} \sqrt{c \sin (a+b x)}}{\sqrt{c} \sqrt{d \cos (a+b x)}}\right )}{\sqrt{2} b \sqrt{d}}+\frac{\sqrt{c} \tan ^{-1}\left (\frac{\sqrt{2} \sqrt{d} \sqrt{c \sin (a+b x)}}{\sqrt{c} \sqrt{d \cos (a+b x)}}+1\right )}{\sqrt{2} b \sqrt{d}}+\frac{\sqrt{c} \log \left (-\frac{\sqrt{2} \sqrt{d} \sqrt{c \sin (a+b x)}}{\sqrt{d \cos (a+b x)}}+\sqrt{c} \tan (a+b x)+\sqrt{c}\right )}{2 \sqrt{2} b \sqrt{d}}-\frac{\sqrt{c} \log \left (\frac{\sqrt{2} \sqrt{d} \sqrt{c \sin (a+b x)}}{\sqrt{d \cos (a+b x)}}+\sqrt{c} \tan (a+b x)+\sqrt{c}\right )}{2 \sqrt{2} b \sqrt{d}} \]
Antiderivative was successfully verified.
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Rule 2574
Rule 297
Rule 1162
Rule 617
Rule 204
Rule 1165
Rule 628
Rubi steps
\begin{align*} \int \frac{\sqrt{c \sin (a+b x)}}{\sqrt{d \cos (a+b x)}} \, dx &=\frac{(2 c d) \operatorname{Subst}\left (\int \frac{x^2}{c^2+d^2 x^4} \, dx,x,\frac{\sqrt{c \sin (a+b x)}}{\sqrt{d \cos (a+b x)}}\right )}{b}\\ &=-\frac{c \operatorname{Subst}\left (\int \frac{c-d x^2}{c^2+d^2 x^4} \, dx,x,\frac{\sqrt{c \sin (a+b x)}}{\sqrt{d \cos (a+b x)}}\right )}{b}+\frac{c \operatorname{Subst}\left (\int \frac{c+d x^2}{c^2+d^2 x^4} \, dx,x,\frac{\sqrt{c \sin (a+b x)}}{\sqrt{d \cos (a+b x)}}\right )}{b}\\ &=\frac{c \operatorname{Subst}\left (\int \frac{1}{\frac{c}{d}-\frac{\sqrt{2} \sqrt{c} x}{\sqrt{d}}+x^2} \, dx,x,\frac{\sqrt{c \sin (a+b x)}}{\sqrt{d \cos (a+b x)}}\right )}{2 b d}+\frac{c \operatorname{Subst}\left (\int \frac{1}{\frac{c}{d}+\frac{\sqrt{2} \sqrt{c} x}{\sqrt{d}}+x^2} \, dx,x,\frac{\sqrt{c \sin (a+b x)}}{\sqrt{d \cos (a+b x)}}\right )}{2 b d}+\frac{\sqrt{c} \operatorname{Subst}\left (\int \frac{\frac{\sqrt{2} \sqrt{c}}{\sqrt{d}}+2 x}{-\frac{c}{d}-\frac{\sqrt{2} \sqrt{c} x}{\sqrt{d}}-x^2} \, dx,x,\frac{\sqrt{c \sin (a+b x)}}{\sqrt{d \cos (a+b x)}}\right )}{2 \sqrt{2} b \sqrt{d}}+\frac{\sqrt{c} \operatorname{Subst}\left (\int \frac{\frac{\sqrt{2} \sqrt{c}}{\sqrt{d}}-2 x}{-\frac{c}{d}+\frac{\sqrt{2} \sqrt{c} x}{\sqrt{d}}-x^2} \, dx,x,\frac{\sqrt{c \sin (a+b x)}}{\sqrt{d \cos (a+b x)}}\right )}{2 \sqrt{2} b \sqrt{d}}\\ &=\frac{\sqrt{c} \log \left (\sqrt{c}-\frac{\sqrt{2} \sqrt{d} \sqrt{c \sin (a+b x)}}{\sqrt{d \cos (a+b x)}}+\sqrt{c} \tan (a+b x)\right )}{2 \sqrt{2} b \sqrt{d}}-\frac{\sqrt{c} \log \left (\sqrt{c}+\frac{\sqrt{2} \sqrt{d} \sqrt{c \sin (a+b x)}}{\sqrt{d \cos (a+b x)}}+\sqrt{c} \tan (a+b x)\right )}{2 \sqrt{2} b \sqrt{d}}+\frac{\sqrt{c} \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1-\frac{\sqrt{2} \sqrt{d} \sqrt{c \sin (a+b x)}}{\sqrt{c} \sqrt{d \cos (a+b x)}}\right )}{\sqrt{2} b \sqrt{d}}-\frac{\sqrt{c} \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1+\frac{\sqrt{2} \sqrt{d} \sqrt{c \sin (a+b x)}}{\sqrt{c} \sqrt{d \cos (a+b x)}}\right )}{\sqrt{2} b \sqrt{d}}\\ &=-\frac{\sqrt{c} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt{d} \sqrt{c \sin (a+b x)}}{\sqrt{c} \sqrt{d \cos (a+b x)}}\right )}{\sqrt{2} b \sqrt{d}}+\frac{\sqrt{c} \tan ^{-1}\left (1+\frac{\sqrt{2} \sqrt{d} \sqrt{c \sin (a+b x)}}{\sqrt{c} \sqrt{d \cos (a+b x)}}\right )}{\sqrt{2} b \sqrt{d}}+\frac{\sqrt{c} \log \left (\sqrt{c}-\frac{\sqrt{2} \sqrt{d} \sqrt{c \sin (a+b x)}}{\sqrt{d \cos (a+b x)}}+\sqrt{c} \tan (a+b x)\right )}{2 \sqrt{2} b \sqrt{d}}-\frac{\sqrt{c} \log \left (\sqrt{c}+\frac{\sqrt{2} \sqrt{d} \sqrt{c \sin (a+b x)}}{\sqrt{d \cos (a+b x)}}+\sqrt{c} \tan (a+b x)\right )}{2 \sqrt{2} b \sqrt{d}}\\ \end{align*}
Mathematica [C] time = 0.0623537, size = 67, normalized size = 0.24 \[ \frac{2 \cos ^2(a+b x)^{3/4} \tan (a+b x) \sqrt{c \sin (a+b x)} \, _2F_1\left (\frac{3}{4},\frac{3}{4};\frac{7}{4};\sin ^2(a+b x)\right )}{3 b \sqrt{d \cos (a+b x)}} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.083, size = 271, normalized size = 1. \begin{align*} -{\frac{\sqrt{2}\sin \left ( bx+a \right ) }{2\,b \left ( -1+\cos \left ( bx+a \right ) \right ) }\sqrt{c\sin \left ( bx+a \right ) } \left ( i{\it EllipticPi} \left ( \sqrt{{\frac{1-\cos \left ( bx+a \right ) +\sin \left ( bx+a \right ) }{\sin \left ( bx+a \right ) }}},{\frac{1}{2}}-{\frac{i}{2}},{\frac{\sqrt{2}}{2}} \right ) -i{\it EllipticPi} \left ( \sqrt{{\frac{1-\cos \left ( bx+a \right ) +\sin \left ( bx+a \right ) }{\sin \left ( bx+a \right ) }}},{\frac{1}{2}}+{\frac{i}{2}},{\frac{\sqrt{2}}{2}} \right ) -{\it EllipticPi} \left ( \sqrt{{\frac{1-\cos \left ( bx+a \right ) +\sin \left ( bx+a \right ) }{\sin \left ( bx+a \right ) }}},{\frac{1}{2}}-{\frac{i}{2}},{\frac{\sqrt{2}}{2}} \right ) -{\it EllipticPi} \left ( \sqrt{{\frac{1-\cos \left ( bx+a \right ) +\sin \left ( bx+a \right ) }{\sin \left ( bx+a \right ) }}},{\frac{1}{2}}+{\frac{i}{2}},{\frac{\sqrt{2}}{2}} \right ) \right ) \sqrt{{\frac{-1+\cos \left ( bx+a \right ) }{\sin \left ( bx+a \right ) }}}\sqrt{{\frac{-1+\cos \left ( bx+a \right ) +\sin \left ( bx+a \right ) }{\sin \left ( bx+a \right ) }}}\sqrt{{\frac{1-\cos \left ( bx+a \right ) +\sin \left ( bx+a \right ) }{\sin \left ( bx+a \right ) }}}{\frac{1}{\sqrt{d\cos \left ( bx+a \right ) }}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{c \sin \left (b x + a\right )}}{\sqrt{d \cos \left (b x + a\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{c \sin{\left (a + b x \right )}}}{\sqrt{d \cos{\left (a + b x \right )}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{c \sin \left (b x + a\right )}}{\sqrt{d \cos \left (b x + a\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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